What are the solutions to the equation x^2+6x-4=0 ?

The solutions to the equation x^2+6x-4=0 are x=-3+sqrt(13),x=-3-sqrt(13)

Find the zeros of x^2+6x-4=0

The zeros of x^2+6x-4=0 are x=-3+sqrt(13),x=-3-sqrt(13)

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x^{2} + 6 x - 4 = 0

x = - 3 + 13, x = - 3 - 13

Decimal Notation

x = 0.60555 \dots, x = - 6.60555 \dots

Solution steps

x^{2} + 6 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 4 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 4) = 213

x_{1, 2} = \frac{- 6 \pm 2 13}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 2 13}{2 \cdot 1}, x_{2} = \frac{- 6 - 2 13}{2 \cdot 1}

x = \frac{- 6 + 2 13}{2 \cdot 1} : - 3 + 13

x = \frac{- 6 - 2 13}{2 \cdot 1} : - 3 - 13

The solutions to the quadratic equation are:

x = - 3 + 13, x = - 3 - 13

(v - 7) (v - 4) = 0

5 (u + 1) - 7 = 3 (u - 1) + 2 u

- 6 c = 54

\frac{1}{9} x^{2} + \frac{2}{15} x y + \frac{1}{25} y^{2}

y, y^{2} = x^{x + 2}

What are the solutions to the equation x^2+6x-4=0 ?
The solutions to the equation x^2+6x-4=0 are x=-3+sqrt(13),x=-3-sqrt(13)
Find the zeros of x^2+6x-4=0
The zeros of x^2+6x-4=0 are x=-3+sqrt(13),x=-3-sqrt(13)