What are the solutions to the equation (v-7)(v-4)=0 ?

The solutions to the equation (v-7)(v-4)=0 are v=7,v=4

Find the zeros of (v-7)(v-4)=0

The zeros of (v-7)(v-4)=0 are v=7,v=4

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(v - 7) (v - 4) = 0

v = 7, v = 4

Solution steps

(v - 7) (v - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

v - 7 = 0 or v - 4 = 0

Solve

v - 7 = 0 : v = 7

Solve

v - 4 = 0 : v = 4

The solutions to the quadratic equation are:

v = 7, v = 4

5 (u + 1) - 7 = 3 (u - 1) + 2 u

- 6 c = 54

\frac{1}{9} x^{2} + \frac{2}{15} x y + \frac{1}{25} y^{2}

y, y^{2} = x^{x + 2}

4 x + 4 \leq 9 x + 84 x + 4 \leq 9 x + 8

What are the solutions to the equation (v-7)(v-4)=0 ?
The solutions to the equation (v-7)(v-4)=0 are v=7,v=4
Find the zeros of (v-7)(v-4)=0
The zeros of (v-7)(v-4)=0 are v=7,v=4