What are the solutions to the equation 4x^2+4x-168=0 ?

The solutions to the equation 4x^2+4x-168=0 are x=6,x=-7

Find the zeros of 4x^2+4x-168=0

The zeros of 4x^2+4x-168=0 are x=6,x=-7

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4 x^{2} + 4 x - 168 = 0

x = 6, x = - 7

Solution steps

4 x^{2} + 4 x - 168 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 4 ( - 168 )}{2 \cdot 4}

4^{2} - 4 \cdot 4 (- 168) = 52

x_{1, 2} = \frac{- 4 \pm 52}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 4 + 52}{2 \cdot 4}, x_{2} = \frac{- 4 - 52}{2 \cdot 4}

x = \frac{- 4 + 52}{2 \cdot 4} : 6

x = \frac{- 4 - 52}{2 \cdot 4} : - 7

The solutions to the quadratic equation are:

x = 6, x = - 7

\frac{y ^{2}}{y ^{- 5}}

3 y^{2} - 7 y + 2 = 0

\frac{1}{4} - 3

45 \cdot 415

lo g_{\frac{1}{2}} (2)

What are the solutions to the equation 4x^2+4x-168=0 ?
The solutions to the equation 4x^2+4x-168=0 are x=6,x=-7
Find the zeros of 4x^2+4x-168=0
The zeros of 4x^2+4x-168=0 are x=6,x=-7