What are the solutions to the equation 2x^2-16x-50=16 ?

The solutions to the equation 2x^2-16x-50=16 are x=11,x=-3

Find the zeros of 2x^2-16x-50=16

The zeros of 2x^2-16x-50=16 are x=11,x=-3

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2 x^{2} - 16 x - 50 = 16

x = 11, x = - 3

Solution steps

2 x^{2} - 16 x - 50 = 16

Move

16

to the left side

2 x^{2} - 16 x - 66 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 2 ( - 66 )}{2 \cdot 2}

(- 16)^{2} - 4 \cdot 2 (- 66) = 28

x_{1, 2} = \frac{- ( - 16 ) \pm 28}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 28}{2 \cdot 2}, x_{2} = \frac{- ( - 16 ) - 28}{2 \cdot 2}

x = \frac{- ( - 16 ) + 28}{2 \cdot 2} : 11

x = \frac{- ( - 16 ) - 28}{2 \cdot 2} : - 3

The solutions to the quadratic equation are:

x = 11, x = - 3

(\frac{- 4 x ^{2}}{2 x ^{- 1}})^{- 1}

4 x^{2} - 25 b^{2}

55 (4 - 87)

\frac{3}{8} x - 17.5 = - 23.5

100 a^{3} + 120 a^{2} - 60 a - 72

What are the solutions to the equation 2x^2-16x-50=16 ?
The solutions to the equation 2x^2-16x-50=16 are x=11,x=-3
Find the zeros of 2x^2-16x-50=16
The zeros of 2x^2-16x-50=16 are x=11,x=-3