What are the solutions to the equation x(x+2)=35 ?

The solutions to the equation x(x+2)=35 are x=5,x=-7

Find the zeros of x(x+2)=35

The zeros of x(x+2)=35 are x=5,x=-7

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x (x + 2) = 35

x = 5, x = - 7

Solution steps

x (x + 2) = 35

Expand

x (x + 2) : x^{2} + 2 x

x^{2} + 2 x = 35

Move

35

to the left side

x^{2} + 2 x - 35 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 35 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 35) = 12

x_{1, 2} = \frac{- 2 \pm 12}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 12}{2 \cdot 1}, x_{2} = \frac{- 2 - 12}{2 \cdot 1}

x = \frac{- 2 + 12}{2 \cdot 1} : 5

x = \frac{- 2 - 12}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

x = 5, x = - 7

- 3 (x + 5) + 2 = 4 (x + 2)

3 \leq x \leq 8

2 ∣ x - 5 ∣ < 32

lo g_{64} (16)

What are the solutions to the equation x(x+2)=35 ?
The solutions to the equation x(x+2)=35 are x=5,x=-7
Find the zeros of x(x+2)=35
The zeros of x(x+2)=35 are x=5,x=-7