What are the solutions to the equation -x^2-4x-7=0 ?

The solutions to the equation -x^2-4x-7=0 are x=-2-sqrt(3)i,x=-2+sqrt(3)i

Find the zeros of -x^2-4x-7=0

The zeros of -x^2-4x-7=0 are x=-2-sqrt(3)i,x=-2+sqrt(3)i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- x^{2} - 4 x - 7 = 0

x = - 2 - 3 i, x = - 2 + 3 i

Solution steps

- x^{2} - 4 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 ( - 1 ) ( - 7 )}{2 ( - 1 )}

Simplify

(- 4)^{2} - 4 (- 1) (- 7) : 23 i

x_{1, 2} = \frac{- ( - 4 ) \pm 2 3 i}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 3 i}{2 ( - 1 )}, x_{2} = \frac{- ( - 4 ) - 2 3 i}{2 ( - 1 )}

x = \frac{- ( - 4 ) + 2 3 i}{2 ( - 1 )} : - 2 - 3 i

x = \frac{- ( - 4 ) - 2 3 i}{2 ( - 1 )} : - 2 + 3 i

The solutions to the quadratic equation are:

x = - 2 - 3 i, x = - 2 + 3 i

4 x^{2} + 4 x + 17 = 0

2 x^{4} + 5 x^{3} - 11 x^{2} - 20 x + 12

4 x = x - 15

(x - 4)^{2} = (x - 2)^{2}

x^{2} + 2 x - 1 \leq 2

What are the solutions to the equation -x^2-4x-7=0 ?
The solutions to the equation -x^2-4x-7=0 are x=-2-sqrt(3)i,x=-2+sqrt(3)i
Find the zeros of -x^2-4x-7=0
The zeros of -x^2-4x-7=0 are x=-2-sqrt(3)i,x=-2+sqrt(3)i