What are the solutions to the equation 4x^2+4x+17=0 ?

The solutions to the equation 4x^2+4x+17=0 are x=-1/2+2i,x=-1/2-2i

Find the zeros of 4x^2+4x+17=0

The zeros of 4x^2+4x+17=0 are x=-1/2+2i,x=-1/2-2i

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4 x^{2} + 4 x + 17 = 0

x = - \frac{1}{2} + 2 i, x = - \frac{1}{2} - 2 i

Solution steps

4 x^{2} + 4 x + 17 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 4 \cdot 17}{2 \cdot 4}

Simplify

4^{2} - 4 \cdot 4 \cdot 17 : 16 i

x_{1, 2} = \frac{- 4 \pm 16 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 4 + 16 i}{2 \cdot 4}, x_{2} = \frac{- 4 - 16 i}{2 \cdot 4}

x = \frac{- 4 + 16 i}{2 \cdot 4} : - \frac{1}{2} + 2 i

x = \frac{- 4 - 16 i}{2 \cdot 4} : - \frac{1}{2} - 2 i

The solutions to the quadratic equation are:

x = - \frac{1}{2} + 2 i, x = - \frac{1}{2} - 2 i

2 x^{4} + 5 x^{3} - 11 x^{2} - 20 x + 12

4 x = x - 15

(x - 4)^{2} = (x - 2)^{2}

x^{2} + 2 x - 1 \leq 2

x^{2} - 4 = 1

What are the solutions to the equation 4x^2+4x+17=0 ?
The solutions to the equation 4x^2+4x+17=0 are x=-1/2+2i,x=-1/2-2i
Find the zeros of 4x^2+4x+17=0
The zeros of 4x^2+4x+17=0 are x=-1/2+2i,x=-1/2-2i