What are the solutions to the equation x^2-3/5 x=60 ?

The solutions to the equation x^2-3/5 x=60 are x=(3+sqrt(6009))/(10),x=(3-sqrt(6009))/(10)

Find the zeros of x^2-3/5 x=60

The zeros of x^2-3/5 x=60 are x=(3+sqrt(6009))/(10),x=(3-sqrt(6009))/(10)

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x^{2} - \frac{3}{5} x = 60

x = \frac{3 + 6009}{10}, x = \frac{3 - 6009}{10}

Decimal Notation

x = 8.05177 \dots, x = - 7.45177 \dots

Solution steps

x^{2} - \frac{3}{5} x = 60

Multiply both sides by

5

5 x^{2} - 3 x = 300

Move

300

to the left side

5 x^{2} - 3 x - 300 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 5 ( - 300 )}{2 \cdot 5}

(- 3)^{2} - 4 \cdot 5 (- 300) = 6009

x_{1, 2} = \frac{- ( - 3 ) \pm 6009}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 6009}{2 \cdot 5}, x_{2} = \frac{- ( - 3 ) - 6009}{2 \cdot 5}

x = \frac{- ( - 3 ) + 6009}{2 \cdot 5} : \frac{3 + 6009}{10}

x = \frac{- ( - 3 ) - 6009}{2 \cdot 5} : \frac{3 - 6009}{10}

The solutions to the quadratic equation are:

x = \frac{3 + 6009}{10}, x = \frac{3 - 6009}{10}

5 (x - 3) = 10 x - 15

\frac{x - 7}{5} - \frac{x - 11}{6} + \frac{x - 10}{7} = 2

- 6 \leq x \leq 6

\frac{2}{p ^{2} + pq} + \frac{3}{pq - q ^{2}}

\frac{2}{x} \frac{5}{y}

What are the solutions to the equation x^2-3/5 x=60 ?
The solutions to the equation x^2-3/5 x=60 are x=(3+sqrt(6009))/(10),x=(3-sqrt(6009))/(10)
Find the zeros of x^2-3/5 x=60
The zeros of x^2-3/5 x=60 are x=(3+sqrt(6009))/(10),x=(3-sqrt(6009))/(10)