What are the solutions to the equation (x+8)(x-3)=0 ?

The solutions to the equation (x+8)(x-3)=0 are x=-8,x=3

Find the zeros of (x+8)(x-3)=0

The zeros of (x+8)(x-3)=0 are x=-8,x=3

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(x + 8) (x - 3) = 0

x = - 8, x = 3

Solution steps

(x + 8) (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 8 = 0 or x - 3 = 0

Solve

x + 8 = 0 : x = - 8

Solve

x - 3 = 0 : x = 3

The solutions to the quadratic equation are:

x = - 8, x = 3

- x^{2} + 8 x = 0

5 m^{3} + 30 m^{2} - 35 m

\frac{2}{5} x - \frac{3}{2} x = \frac{3}{4} x + 3

2 y^{2} + 2 y - 12

1 - i

What are the solutions to the equation (x+8)(x-3)=0 ?
The solutions to the equation (x+8)(x-3)=0 are x=-8,x=3
Find the zeros of (x+8)(x-3)=0
The zeros of (x+8)(x-3)=0 are x=-8,x=3