What are the solutions to the equation 5x^2+40x+60=0 ?

The solutions to the equation 5x^2+40x+60=0 are x=-2,x=-6

Find the zeros of 5x^2+40x+60=0

The zeros of 5x^2+40x+60=0 are x=-2,x=-6

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5 x^{2} + 40 x + 60 = 0

x = - 2, x = - 6

Solution steps

5 x^{2} + 40 x + 60 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 40 \pm 4 0 ^{2} - 4 \cdot 5 \cdot 60}{2 \cdot 5}

4 0^{2} - 4 \cdot 5 \cdot 60 = 20

x_{1, 2} = \frac{- 40 \pm 20}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 40 + 20}{2 \cdot 5}, x_{2} = \frac{- 40 - 20}{2 \cdot 5}

x = \frac{- 40 + 20}{2 \cdot 5} : - 2

x = \frac{- 40 - 20}{2 \cdot 5} : - 6

The solutions to the quadratic equation are:

x = - 2, x = - 6

- 16 t^{2} + 70 t + 5 = 70

81 x^{10} - 54 x^{5} y^{3} + 9

\frac{21.33 - 9.16}{3.5 - 1.5}

6 x + 4 < 2 + 5 x

\frac{5}{2} \cdot 3

What are the solutions to the equation 5x^2+40x+60=0 ?
The solutions to the equation 5x^2+40x+60=0 are x=-2,x=-6
Find the zeros of 5x^2+40x+60=0
The zeros of 5x^2+40x+60=0 are x=-2,x=-6