What are the solutions to the equation -16t^2+70t+5=70 ?

The solutions to the equation -16t^2+70t+5=70 are t=(35-sqrt(185))/(16),t=(35+sqrt(185))/(16)

Find the zeros of -16t^2+70t+5=70

The zeros of -16t^2+70t+5=70 are t=(35-sqrt(185))/(16),t=(35+sqrt(185))/(16)

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- 16 t^{2} + 70 t + 5 = 70

t = \frac{35 - 185}{16}, t = \frac{35 + 185}{16}

Decimal Notation

t = 1.33740 \dots, t = 3.03759 \dots

Solution steps

- 16 t^{2} + 70 t + 5 = 70

Move

70

to the left side

- 16 t^{2} + 70 t - 65 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 70 \pm 7 0 ^{2} - 4 ( - 16 ) ( - 65 )}{2 ( - 16 )}

7 0^{2} - 4 (- 16) (- 65) = 2185

t_{1, 2} = \frac{- 70 \pm 2 185}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 70 + 2 185}{2 ( - 16 )}, t_{2} = \frac{- 70 - 2 185}{2 ( - 16 )}

t = \frac{- 70 + 2 185}{2 ( - 16 )} : \frac{35 - 185}{16}

t = \frac{- 70 - 2 185}{2 ( - 16 )} : \frac{35 + 185}{16}

The solutions to the quadratic equation are:

t = \frac{35 - 185}{16}, t = \frac{35 + 185}{16}

81 x^{10} - 54 x^{5} y^{3} + 9

\frac{21.33 - 9.16}{3.5 - 1.5}

6 x + 4 < 2 + 5 x

\frac{5}{2} \cdot 3

(x + 4)^{2} = 25

What are the solutions to the equation -16t^2+70t+5=70 ?
The solutions to the equation -16t^2+70t+5=70 are t=(35-sqrt(185))/(16),t=(35+sqrt(185))/(16)
Find the zeros of -16t^2+70t+5=70
The zeros of -16t^2+70t+5=70 are t=(35-sqrt(185))/(16),t=(35+sqrt(185))/(16)