What are the solutions to the equation -3x^2-4x-8=0 ?

The solutions to the equation -3x^2-4x-8=0 are x=-2/3-i(2sqrt(5))/3 ,x=-2/3+i(2sqrt(5))/3

Find the zeros of -3x^2-4x-8=0

The zeros of -3x^2-4x-8=0 are x=-2/3-i(2sqrt(5))/3 ,x=-2/3+i(2sqrt(5))/3

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- 3 x^{2} - 4 x - 8 = 0

x = - \frac{2}{3} - i \frac{2 5}{3}, x = - \frac{2}{3} + i \frac{2 5}{3}

Solution steps

- 3 x^{2} - 4 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 ( - 3 ) ( - 8 )}{2 ( - 3 )}

Simplify

(- 4)^{2} - 4 (- 3) (- 8) : 45 i

x_{1, 2} = \frac{- ( - 4 ) \pm 4 5 i}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 4 5 i}{2 ( - 3 )}, x_{2} = \frac{- ( - 4 ) - 4 5 i}{2 ( - 3 )}

x = \frac{- ( - 4 ) + 4 5 i}{2 ( - 3 )} : - \frac{2}{3} - i \frac{2 5}{3}

x = \frac{- ( - 4 ) - 4 5 i}{2 ( - 3 )} : - \frac{2}{3} + i \frac{2 5}{3}

The solutions to the quadratic equation are:

x = - \frac{2}{3} - i \frac{2 5}{3}, x = - \frac{2}{3} + i \frac{2 5}{3}

x^{2} + 2 ∣ x - 3 ∣ - 9 > 0

16 x^{2} + 24 x y + 9 y^{2}

x^{4} y^{3} \cdot (2 y^{2})^{0}

x^{2} - 3 x = (x + 3) (x - 4)

∣ x - 6 ∣ > 7

What are the solutions to the equation -3x^2-4x-8=0 ?
The solutions to the equation -3x^2-4x-8=0 are x=-2/3-i(2sqrt(5))/3 ,x=-2/3+i(2sqrt(5))/3
Find the zeros of -3x^2-4x-8=0
The zeros of -3x^2-4x-8=0 are x=-2/3-i(2sqrt(5))/3 ,x=-2/3+i(2sqrt(5))/3