What is 3/(b^2-4b-5)-2/(b^2-6b+5) ?

The solution to 3/(b^2-4b-5)-2/(b^2-6b+5) is 1/((b+1)(b-1))

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simplify 3/(b^2-4b-5)-2/(b^2-6b+5)

simplify

\frac{3}{b ^{2} - 4 b - 5} - \frac{2}{b ^{2} - 6 b + 5}

\frac{1}{( b + 1 ) ( b - 1 )}

Solution steps

\frac{3}{b ^{2} - 4 b - 5} - \frac{2}{b ^{2} - 6 b + 5}

Least Common Multiplier of

b^{2} - 4 b - 5, b^{2} - 6 b + 5 : (b + 1) (b - 5) (b - 1)

Adjust Fractions based on the LCM

= \frac{3 ( b - 1 )}{( b + 1 ) ( b - 5 ) ( b - 1 )} - \frac{2 ( b + 1 )}{( b + 1 ) ( b - 5 ) ( b - 1 )}

Apply the fraction rule:

\frac{a}{c} - \frac{b}{c} = \frac{a - b}{c}

= \frac{3 ( b - 1 ) - 2 ( b + 1 )}{( b + 1 ) ( b - 5 ) ( b - 1 )}

Simplify

3 (b - 1) - 2 (b + 1) : b - 5

= \frac{b - 5}{( b + 1 ) ( b - 5 ) ( b - 1 )}

Cancel the common factor:

b - 5

= \frac{1}{( b + 1 ) ( b - 1 )}

72 x + 15 x^{2} - 3 x^{3}

x^{2} - 3 x - 2 = 0

23 x + 5 > - 110

3 x + 5 = 11

- 6 w + 12 > 48

What is 3/(b^2-4b-5)-2/(b^2-6b+5) ?
The solution to 3/(b^2-4b-5)-2/(b^2-6b+5) is 1/((b+1)(b-1))