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Popular >

(x^2+4)(x+3)(x-5)<= 0

Solution

(x^{2} + 4) (x + 3) (x - 5) \leq 0

Solution

- 3 \leq x \leq 5

+1

Solution steps

(x^{2} + 4) (x + 3) (x - 5) \leq 0

Identify the intervals

- 3 \leq x \leq 5

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\frac{a ^{2} b ^{2}}{ab}

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3 x - 8 + 2 x + 15 \leq 9 x - 23 + 2 x + 12

2 ∣ 3 x + 1 ∣ = 20

(x - 12) 4 = 36

simplify e^{-0.5}simplify

e^{- 0.5}

Frequently Asked Questions (FAQ)

What is (x^2+4)(x+3)(x-5)<= 0 ?
The solution to (x^2+4)(x+3)(x-5)<= 0 is -3<= x<= 5