What is (n-6)/(n^2-13n+42) ?

The solution to (n-6)/(n^2-13n+42) is 1/(n-7)

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simplify (n-6)/(n^2-13n+42)

simplify

\frac{n - 6}{n ^{2} - 13 n + 42}

\frac{1}{n - 7}

Solution steps

\frac{n - 6}{n ^{2} - 13 n + 42}

Factor

n^{2} - 13 n + 42 : (n - 6) (n - 7)

= \frac{n - 6}{( n - 6 ) ( n - 7 )}

Cancel the common factor:

n - 6

= \frac{1}{n - 7}

\frac{5}{2 2}

\frac{1}{4} \div 4

\frac{36}{12}

(8 x^{6} y^{- 15} z^{3})^{\frac{2}{3}} \cdot (49 x^{- 2} y^{8} z^{2})^{- \frac{1}{2}}

(x^{2} + 8 x + 8) + (- 10 x^{2} + 5 x)