What is (x^2-5x+4)/(x^2-1) ?

The solution to (x^2-5x+4)/(x^2-1) is (x-4)/(x+1)

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simplify (x^2-5x+4)/(x^2-1)

simplify

\frac{x ^{2} - 5 x + 4}{x ^{2} - 1}

\frac{x - 4}{x + 1}

Solution steps

\frac{x ^{2} - 5 x + 4}{x ^{2} - 1}

Factor

x^{2} - 5 x + 4 : (x - 1) (x - 4)

= \frac{( x - 1 ) ( x - 4 )}{x ^{2} - 1}

Factor

x^{2} - 1 : (x + 1) (x - 1)

= \frac{( x - 1 ) ( x - 4 )}{( x + 1 ) ( x - 1 )}

Cancel the common factor:

x - 1

= \frac{x - 4}{x + 1}

3.14 \cdot 8^{2}

(z - 3) (z - 4)

\frac{14 a ^{3} b ^{4}}{- 2 a b ^{2}}

\frac{2 x ^{3} - x ^{2} - 25 x - 12}{x + 3}

- 6 (a + 8)