What is (2x^3-x^2-25x-12)/(x+3) ?

The solution to (2x^3-x^2-25x-12)/(x+3) is (2x+1)(x-4)

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simplify (2x^3-x^2-25x-12)/(x+3)

simplify

\frac{2 x ^{3} - x ^{2} - 25 x - 12}{x + 3}

(2 x + 1) (x - 4)

Solution steps

\frac{2 x ^{3} - x ^{2} - 25 x - 12}{x + 3}

Use the rational root theorem

= \frac{( 2 x + 1 ) \frac{2 x ^{3} - x ^{2} - 25 x - 12}{2 x + 1}}{x + 3}

\frac{2 x ^{3} - x ^{2} - 25 x - 12}{2 x + 1} = x^{2} - x - 12

= \frac{( 2 x + 1 ) ( x ^{2} - x - 12 )}{x + 3}

Factor

x^{2} - x - 12 : (x + 3) (x - 4)

= \frac{( 2 x + 1 ) ( x + 3 ) ( x - 4 )}{x + 3}

Cancel the common factor:

x + 3

= (2 x + 1) (x - 4)

- 6 (a + 8)

1 - 8

\frac{4}{3} π r^{3}

- 4 \div 4

\frac{\frac{6 x ^{2}}{11 y ^{3}}}{\frac{9 x ^{4}}{22 y ^{2}}}

What is (2x^3-x^2-25x-12)/(x+3) ?
The solution to (2x^3-x^2-25x-12)/(x+3) is (2x+1)(x-4)