What are the solutions to the equation 2x^2=26 ?

The solutions to the equation 2x^2=26 are x=sqrt(13),x=-sqrt(13)

Find the zeros of 2x^2=26

The zeros of 2x^2=26 are x=sqrt(13),x=-sqrt(13)

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2 x^{2} = 26

x = 13, x = - 13

Solution steps

2 x^{2} = 26

Divide both sides by

2

x^{2} = 13

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 13, x = - 13

\frac{3}{2} - 5

0 + 4

\frac{7}{25 z ^{3} y} - \frac{1}{35 z ^{2} y}

- \frac{3}{5} (5 k - 10) < - 15

\frac{1}{12}

What are the solutions to the equation 2x^2=26 ?
The solutions to the equation 2x^2=26 are x=sqrt(13),x=-sqrt(13)
Find the zeros of 2x^2=26
The zeros of 2x^2=26 are x=sqrt(13),x=-sqrt(13)