What is 7/(25z^3y)-1/(35z^2y) ?

The solution to 7/(25z^3y)-1/(35z^2y) is (49-5z)/(175z^3y)

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simplify 7/(25z^3y)-1/(35z^2y)

simplify

\frac{7}{25 z ^{3} y} - \frac{1}{35 z ^{2} y}

\frac{49 - 5 z}{175 z ^{3} y}

Solution steps

\frac{7}{25 z ^{3} y} - \frac{1}{35 z ^{2} y}

Least Common Multiplier of

25 z^{3} y, 35 z^{2} y : 175 z^{3} y

Adjust Fractions based on the LCM

= \frac{49}{175 z ^{3} y} - \frac{5 z}{175 z ^{3} y}

Apply the fraction rule:

\frac{a}{c} - \frac{b}{c} = \frac{a - b}{c}

= \frac{49 - 5 z}{175 z ^{3} y}

- \frac{3}{5} (5 k - 10) < - 15

\frac{1}{12}

60 - 60 x = (8 x + 4) (x - 1)

- 10 \leq 5 + x < - 5

2 (3 - 7 x) + 3 x < 3 (5 + 2 x)

What is 7/(25z^3y)-1/(35z^2y) ?
The solution to 7/(25z^3y)-1/(35z^2y) is (49-5z)/(175z^3y)