What are the solutions to the equation x^2+18x+90=0 ?

The solutions to the equation x^2+18x+90=0 are x=-9+3i,x=-9-3i

Find the zeros of x^2+18x+90=0

The zeros of x^2+18x+90=0 are x=-9+3i,x=-9-3i

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x^{2} + 18 x + 90 = 0

x = - 9 + 3 i, x = - 9 - 3 i

Solution steps

x^{2} + 18 x + 90 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 1 \cdot 90}{2 \cdot 1}

Simplify

1 8^{2} - 4 \cdot 1 \cdot 90 : 6 i

x_{1, 2} = \frac{- 18 \pm 6 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 18 + 6 i}{2 \cdot 1}, x_{2} = \frac{- 18 - 6 i}{2 \cdot 1}

x = \frac{- 18 + 6 i}{2 \cdot 1} : - 9 + 3 i

x = \frac{- 18 - 6 i}{2 \cdot 1} : - 9 - 3 i

The solutions to the quadratic equation are:

x = - 9 + 3 i, x = - 9 - 3 i

16 r^{2} - 25

- 30 = 5 (x - 9)

lo g_{2} (\frac{1}{8}) = y

14 - (5 x - 1) (2 x + 3) = 17 - (10 x + 1) (x - 6)

\frac{x}{p ^{2}} + \frac{y}{pq}

What are the solutions to the equation x^2+18x+90=0 ?
The solutions to the equation x^2+18x+90=0 are x=-9+3i,x=-9-3i
Find the zeros of x^2+18x+90=0
The zeros of x^2+18x+90=0 are x=-9+3i,x=-9-3i