What is (-3^{-2})/(4^{-1)} ?

The solution to (-3^{-2})/(4^{-1)} is -4/9

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simplify (-3^{-2})/(4^{-1)}

simplify

\frac{- 3 ^{- 2}}{4 ^{- 1}}

- \frac{4}{9}

Decimal Notation

- 0.44444 \dots

Solution steps

\frac{- 3 ^{- 2}}{4 ^{- 1}}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{3 ^{- 2}}{4 ^{- 1}}

3^{- 2} = \frac{1}{9}

= - \frac{\frac{1}{9}}{4 ^{- 1}}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

\frac{\frac{1}{9}}{4 ^{- 1}} = \frac{1}{9 \cdot 4 ^{- 1}}

= - \frac{1}{9 \cdot 4 ^{- 1}}

Simplify

9 \cdot 4^{- 1} : \frac{9}{4}

= - \frac{1}{\frac{9}{4}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

\frac{1}{\frac{9}{4}} = \frac{4}{9}

= - \frac{4}{9}

(- 4 x - 3) (2 x^{2} - 3 x + 4)

\frac{4 2 ^{642}}{22}

\frac{15}{21}

\frac{28}{36}

- 2 \frac{1}{2}