What is (x^2+8x+12)/(x^2+3x-18) ?

The solution to (x^2+8x+12)/(x^2+3x-18) is (x+2)/(x-3)

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simplify (x^2+8x+12)/(x^2+3x-18)

simplify

\frac{x ^{2} + 8 x + 12}{x ^{2} + 3 x - 18}

\frac{x + 2}{x - 3}

Solution steps

\frac{x ^{2} + 8 x + 12}{x ^{2} + 3 x - 18}

Factor

x^{2} + 8 x + 12 : (x + 2) (x + 6)

= \frac{( x + 2 ) ( x + 6 )}{x ^{2} + 3 x - 18}

Factor

x^{2} + 3 x - 18 : (x - 3) (x + 6)

= \frac{( x + 2 ) ( x + 6 )}{( x - 3 ) ( x + 6 )}

Cancel the common factor:

x + 6

= \frac{x + 2}{x - 3}

\frac{x ^{- 2}}{x}

(4 x - 5) (4 x + 5)

(2 a + b)^{3}

\frac{x - 1}{1 - x}

\frac{lo g _{10} ( a )}{lo g _{10} ( b )}

What is (x^2+8x+12)/(x^2+3x-18) ?
The solution to (x^2+8x+12)/(x^2+3x-18) is (x+2)/(x-3)