What is (log_{10}(a))/(log_{10)(b)} ?

The solution to (log_{10}(a))/(log_{10)(b)} is log_{b}(a)

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simplify (log_{10}(a))/(log_{10)(b)}

simplify

\frac{lo g _{10} ( a )}{lo g _{10} ( b )}

lo g_{b} (a)

Solution steps

\frac{lo g _{10} ( a )}{lo g _{10} ( b )}

Apply log rule:

\frac{lo g _{c} ( b )}{lo g _{c} ( a )} = lo g_{a} (b)

\frac{lo g _{10} ( a )}{lo g _{10} ( b )} = lo g_{b} (a)

= lo g_{b} (a)

\frac{125}{100}

(11 - 7 i) (8 - 6 i)

\frac{13 + 7 i}{- 3 - 10 i}

5 i \cdot i \cdot (- 2) i

(- 1 + 8 i)^{2}

What is (log_{10}(a))/(log_{10)(b)} ?
The solution to (log_{10}(a))/(log_{10)(b)} is log_{b}(a)