What is (3+10i)/(9-i) ?

The solution to (3+10i)/(9-i) is 17/82+93/82 i

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simplify (3+10i)/(9-i)

simplify

\frac{3 + 10 i}{9 - i}

\frac{17}{82} + \frac{93}{82} i

Solution steps

\frac{3 + 10 i}{9 - i}

Multiply by the conjugate

\frac{9 + i}{9 + i}

= \frac{( 3 + 10 i ) ( 9 + i )}{( 9 - i ) ( 9 + i )}

Simplify

\frac{( 3 + 10 i ) ( 9 + i )}{( 9 - i ) ( 9 + i )} : \frac{17 + 93 i}{82}

= \frac{17 + 93 i}{82}

Rewrite in standard complex form:

\frac{17}{82} + \frac{93}{82} i

= \frac{17}{82} + \frac{93}{82} i

(- x + 1)^{3}

- 0.6 a^{2} b \cdot (- 10 a b^{2})

(3 x + 8) (8 - 3 x)

(9 - 10 i) - (- 10 + i)

(x^{3} - 3 x^{2} + 1) (x + 3)