What are the solutions to the equation -56^2+33^2=c^2 ?

The solutions to the equation -56^2+33^2=c^2 are c=sqrt(2047)i,c=-sqrt(2047)i

Find the zeros of -56^2+33^2=c^2

The zeros of -56^2+33^2=c^2 are c=sqrt(2047)i,c=-sqrt(2047)i

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- 5 6^{2} + 3 3^{2} = c^{2}

c = 2047 i, c = - 2047 i

Solution steps

- 5 6^{2} + 3 3^{2} = c^{2}

Switch sides

c^{2} = - 5 6^{2} + 3 3^{2}

Simplify

- 5 6^{2} + 3 3^{2} : - 2047

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = - 2047, c = - - 2047

- 2047 = 2047 i

- - 2047 = - 2047 i

c = 2047 i, c = - 2047 i

(\frac{e}{10})^{1}

y^{2} + 2 y = 35

\frac{5}{6 x ^{7} y ^{4}} \cdot \frac{5}{3 x ^{6} y ^{3}}

- 3 (w + 5) + 5 w = 2 (w - 6)

3 x^{2} = 8 - 2 x

What are the solutions to the equation -56^2+33^2=c^2 ?
The solutions to the equation -56^2+33^2=c^2 are c=sqrt(2047)i,c=-sqrt(2047)i
Find the zeros of -56^2+33^2=c^2
The zeros of -56^2+33^2=c^2 are c=sqrt(2047)i,c=-sqrt(2047)i