What is (9x^6-6x^3-3x)/(-3x) ?

The solution to (9x^6-6x^3-3x)/(-3x) is -(x-1)(3x^4+3x^3+3x^2+x+1)

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simplify (9x^6-6x^3-3x)/(-3x)

simplify

\frac{9 x ^{6} - 6 x ^{3} - 3 x}{- 3 x}

- (x - 1) (3 x^{4} + 3 x^{3} + 3 x^{2} + x + 1)

Solution steps

\frac{9 x ^{6} - 6 x ^{3} - 3 x}{- 3 x}

Factor

9 x^{6} - 6 x^{3} - 3 x : 3 x (3 x^{5} - 2 x^{2} - 1)

= \frac{3 x ( 3 x ^{5} - 2 x ^{2} - 1 )}{- 3 x}

Factor

3 x^{5} - 2 x^{2} - 1 : (x - 1) (3 x^{4} + 3 x^{3} + 3 x^{2} + x + 1)

= \frac{3 x ( x - 1 ) ( 3 x ^{4} + 3 x ^{3} + 3 x ^{2} + x + 1 )}{- 3 x}

Cancel the common factor:

3

= \frac{x ( x - 1 ) ( 3 x ^{4} + 3 x ^{3} + 3 x ^{2} + x + 1 )}{- x}

Cancel the common factor:

x

= \frac{( x - 1 ) ( 3 x ^{4} + 3 x ^{3} + 3 x ^{2} + x + 1 )}{- 1}

Apply the fraction rule:

\frac{a}{- 1} = - a

= - (x - 1) (3 x^{4} + 3 x^{3} + 3 x^{2} + x + 1)

3 a + 2 b - c + 2 a + 3 b + c

- 4 p + (- 6 p)

\frac{3 x ^{3} + 9 x ^{2}}{x ^{2} + 6 x + 9}

(10 x^{2} - x + 1) - (9 x - 2)

\frac{5}{x}

What is (9x^6-6x^3-3x)/(-3x) ?
The solution to (9x^6-6x^3-3x)/(-3x) is -(x-1)(3x^4+3x^3+3x^2+x+1)