What is expand (4x^2-7x+3)(4x-5) ?

The solution to expand (4x^2-7x+3)(4x-5) is 16x^3-48x^2+47x-15

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expand (4x^2-7x+3)(4x-5)

expand

(4 x^{2} - 7 x + 3) (4 x - 5)

16 x^{3} - 48 x^{2} + 47 x - 15

Solution steps

(4 x^{2} - 7 x + 3) (4 x - 5)

Distribute parentheses

= 4 x^{2} \cdot 4 x + 4 x^{2} (- 5) - 7 x \cdot 4 x - 7 x (- 5) + 3 \cdot 4 x + 3 (- 5)

Simplify

4 x^{2} \cdot 4 x + 4 x^{2} (- 5) - 7 x \cdot 4 x - 7 x (- 5) + 3 \cdot 4 x + 3 (- 5) : 16 x^{3} - 48 x^{2} + 47 x - 15

= 16 x^{3} - 48 x^{2} + 47 x - 15

∣ (2 + 3 i) + (6 - 2 i) ∣

mn \cdot (- m^{5} n^{3}) \cdot (- m^{3} n^{8})

4 \cdot 1 0^{- 6}

\frac{21}{9}

5 a^{2} - 6 a + 5 a^{2} - 7 a

What is expand (4x^2-7x+3)(4x-5) ?
The solution to expand (4x^2-7x+3)(4x-5) is 16x^3-48x^2+47x-15