What is (-8-2i)/(6i) ?

The solution to (-8-2i)/(6i) is -1/3+4/3 i

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simplify (-8-2i)/(6i)

simplify

\frac{- 8 - 2 i}{6 i}

- \frac{1}{3} + \frac{4}{3} i

Solution steps

\frac{- 8 - 2 i}{6 i}

Multiply by the conjugate

\frac{- i}{- i}

= \frac{( - 8 - 2 i ) ( - i )}{6 i ( - i )}

Simplify

\frac{( - 8 - 2 i ) ( - i )}{6 i ( - i )} : \frac{8 i - 2}{6}

= \frac{8 i - 2}{6}

Rewrite in standard complex form:

- \frac{1}{3} + \frac{4}{3} i

= - \frac{1}{3} + \frac{4}{3} i

(x + 2) (x - 2) (2 x - 1) (x - 4)

\frac{6}{50}

\frac{sin ( θ )}{1 + cos ( θ )} + \frac{cos ( θ )}{sin ( θ )}

lo g_{125} (9) \cdot lo g_{81} (5)

12 \cdot 12 \cdot 12