What is expand (x-1)(2x^2-3x-8) ?

The solution to expand (x-1)(2x^2-3x-8) is 2x^3-5x^2-5x+8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (x-1)(2x^2-3x-8)

expand

(x - 1) (2 x^{2} - 3 x - 8)

2 x^{3} - 5 x^{2} - 5 x + 8

Solution steps

(x - 1) (2 x^{2} - 3 x - 8)

Distribute parentheses

= x \cdot 2 x^{2} + x (- 3 x) + x (- 8) - 1 \cdot 2 x^{2} - 1 \cdot (- 3 x) - 1 \cdot (- 8)

Simplify

x \cdot 2 x^{2} + x (- 3 x) + x (- 8) - 1 \cdot 2 x^{2} - 1 \cdot (- 3 x) - 1 \cdot (- 8) : 2 x^{3} - 5 x^{2} - 5 x + 8

= 2 x^{3} - 5 x^{2} - 5 x + 8

\frac{5}{2 + i}

x (x + 1) (x - 2)

(7 + 3) (7 - 3)

\frac{8 x ^{2} - 40 x}{2 x ^{2}}

\frac{4 x ^{2} + 16 x}{x ^{2} - 16}

What is expand (x-1)(2x^2-3x-8) ?
The solution to expand (x-1)(2x^2-3x-8) is 2x^3-5x^2-5x+8