What is (8x^2-40x)/(2x^2) ?

The solution to (8x^2-40x)/(2x^2) is (4(x-5))/x

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simplify (8x^2-40x)/(2x^2)

simplify

\frac{8 x ^{2} - 40 x}{2 x ^{2}}

\frac{4 ( x - 5 )}{x}

Solution steps

\frac{8 x ^{2} - 40 x}{2 x ^{2}}

Factor

8 x^{2} - 40 x : 8 x (x - 5)

= \frac{8 x ( x - 5 )}{2 x ^{2}}

Factor the number:

8 = 2 \cdot 4

= \frac{2 \cdot 4 x ( x - 5 )}{2 x ^{2}}

Cancel the common factor:

2

= \frac{4 x ( x - 5 )}{x ^{2}}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

x^{2} = xx

= \frac{4 x ( x - 5 )}{xx}

Cancel the common factor:

x

= \frac{4 ( x - 5 )}{x}

\frac{4 x ^{2} + 16 x}{x ^{2} - 16}

- 9 + 1

\frac{- 2}{- 5}

10 - 7

\frac{2 x ^{4} + 6 x ^{3} - 8 x ^{2}}{2 x ^{2}}