What is (x^3-3x^2-10x+24)/(x+3) ?

The solution to (x^3-3x^2-10x+24)/(x+3) is (x-2)(x-4)

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simplify (x^3-3x^2-10x+24)/(x+3)

simplify

\frac{x ^{3} - 3 x ^{2} - 10 x + 24}{x + 3}

(x - 2) (x - 4)

Solution steps

\frac{x ^{3} - 3 x ^{2} - 10 x + 24}{x + 3}

Use the rational root theorem

= \frac{( x - 2 ) \frac{x ^{3} - 3 x ^{2} - 10 x + 24}{x - 2}}{x + 3}

\frac{x ^{3} - 3 x ^{2} - 10 x + 24}{x - 2} = x^{2} - x - 12

= \frac{( x - 2 ) ( x ^{2} - x - 12 )}{x + 3}

Factor

x^{2} - x - 12 : (x + 3) (x - 4)

= \frac{( x - 2 ) ( x + 3 ) ( x - 4 )}{x + 3}

Cancel the common factor:

x + 3

= (x - 2) (x - 4)

35 \cdot 2

lo g_{a} (a^{x})

lo g_{4} (64) - lo g_{3} (3)

lo g_{- 2} (4)

(- 3 + 7 i) - (- 3 - 8 i)

What is (x^3-3x^2-10x+24)/(x+3) ?
The solution to (x^3-3x^2-10x+24)/(x+3) is (x-2)(x-4)