What is (x^3+3x^2+3x+1)/(x+1) ?

The solution to (x^3+3x^2+3x+1)/(x+1) is (x+1)^2

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simplify (x^3+3x^2+3x+1)/(x+1)

simplify

\frac{x ^{3} + 3 x ^{2} + 3 x + 1}{x + 1}

(x + 1)^{2}

Solution steps

\frac{x ^{3} + 3 x ^{2} + 3 x + 1}{x + 1}

Apply cube of sum rule:

x^{3} + 3 x^{2} y + 3 x y^{2} + y^{3} = (x + y)^{3}

x^{3} + 3 x^{2} + 3 x + 1 = (x + 1)^{3}

= \frac{( x + 1 ) ^{3}}{x + 1}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

(x + 1)^{3} = (x + 1) (x + 1)^{2}

= \frac{( x + 1 ) ( x + 1 ) ^{2}}{x + 1}

Cancel the common factor:

x + 1

= (x + 1)^{2}

x^{3} + x^{2} - 10 x + 8

8 \times \frac{2}{3}

12. 5^{2}

\frac{x + 7}{7 x + 35} \cdot \frac{x ^{2} - 3 x - 40}{x - 8}

2 x^{5} y^{2} (3 x^{4} y^{3} - 5 x)

What is (x^3+3x^2+3x+1)/(x+1) ?
The solution to (x^3+3x^2+3x+1)/(x+1) is (x+1)^2