What is (x+7)/(7x+35)*(x^2-3x-40)/(x-8) ?

The solution to (x+7)/(7x+35)*(x^2-3x-40)/(x-8) is (x+7)/7

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simplify (x+7)/(7x+35)*(x^2-3x-40)/(x-8)

simplify

\frac{x + 7}{7 x + 35} \cdot \frac{x ^{2} - 3 x - 40}{x - 8}

\frac{x + 7}{7}

Solution steps

\frac{x + 7}{7 x + 35} \cdot \frac{x ^{2} - 3 x - 40}{x - 8}

Cancel

\frac{x ^{2} - 3 x - 40}{x - 8} : x + 5

= \frac{x + 7}{7 x + 35} (x + 5)

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( x + 7 ) ( x + 5 )}{7 x + 35}

Factor

7 x + 35 : 7 (x + 5)

= \frac{( x + 7 ) ( x + 5 )}{7 ( x + 5 )}

Cancel the common factor:

x + 5

= \frac{x + 7}{7}

2 x^{5} y^{2} (3 x^{4} y^{3} - 5 x)

\frac{9}{45}

\frac{\frac{x ^{2} - 81}{x - 9}}{\frac{x ^{2} - 17 x + 72}{x - 8}}

1 + 3.322 lo g_{10} (30)

i \times i

What is (x+7)/(7x+35)*(x^2-3x-40)/(x-8) ?
The solution to (x+7)/(7x+35)*(x^2-3x-40)/(x-8) is (x+7)/7