What are the solutions to the equation 6x^2+5x+3=0 ?

The solutions to the equation 6x^2+5x+3=0 are x=-5/12+i(sqrt(47))/(12),x=-5/12-i(sqrt(47))/(12)

Find the zeros of 6x^2+5x+3=0

The zeros of 6x^2+5x+3=0 are x=-5/12+i(sqrt(47))/(12),x=-5/12-i(sqrt(47))/(12)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

6 x^{2} + 5 x + 3 = 0

x = - \frac{5}{12} + i \frac{47}{12}, x = - \frac{5}{12} - i \frac{47}{12}

Solution steps

6 x^{2} + 5 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 6 \cdot 3}{2 \cdot 6}

Simplify

5^{2} - 4 \cdot 6 \cdot 3 : 47 i

x_{1, 2} = \frac{- 5 \pm 47 i}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 5 + 47 i}{2 \cdot 6}, x_{2} = \frac{- 5 - 47 i}{2 \cdot 6}

x = \frac{- 5 + 47 i}{2 \cdot 6} : - \frac{5}{12} + i \frac{47}{12}

x = \frac{- 5 - 47 i}{2 \cdot 6} : - \frac{5}{12} - i \frac{47}{12}

The solutions to the quadratic equation are:

x = - \frac{5}{12} + i \frac{47}{12}, x = - \frac{5}{12} - i \frac{47}{12}

3 x^{2} - 5 x + 2 = 0

- p^{2} = 99

(\frac{2}{x + 1})^{2}

3 x^{2} - 27 x = 0

∣ 3 x - 1 ∣ < 2

What are the solutions to the equation 6x^2+5x+3=0 ?
The solutions to the equation 6x^2+5x+3=0 are x=-5/12+i(sqrt(47))/(12),x=-5/12-i(sqrt(47))/(12)
Find the zeros of 6x^2+5x+3=0
The zeros of 6x^2+5x+3=0 are x=-5/12+i(sqrt(47))/(12),x=-5/12-i(sqrt(47))/(12)