What is (x^2-9)/(x^2+x-6) ?

The solution to (x^2-9)/(x^2+x-6) is (x-3)/(x-2)

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simplify (x^2-9)/(x^2+x-6)

simplify

\frac{x ^{2} - 9}{x ^{2} + x - 6}

\frac{x - 3}{x - 2}

Solution steps

\frac{x ^{2} - 9}{x ^{2} + x - 6}

Factor

x^{2} - 9 : (x + 3) (x - 3)

= \frac{( x + 3 ) ( x - 3 )}{x ^{2} + x - 6}

Factor

x^{2} + x - 6 : (x - 2) (x + 3)

= \frac{( x + 3 ) ( x - 3 )}{( x - 2 ) ( x + 3 )}

Cancel the common factor:

x + 3

= \frac{x - 3}{x - 2}

\frac{- 10 - 7 i}{2 - i}

1 \times 5

(2 x + 1) (x^{2} - 4 x + 8)

\frac{- 3 - 9 i}{- 1 + 10 i}