What is (8x^2-2x+1)+(3x^2+5x-8) ?

The solution to (8x^2-2x+1)+(3x^2+5x-8) is 11x^2+3x-7

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simplify (8x^2-2x+1)+(3x^2+5x-8)

simplify

(8 x^{2} - 2 x + 1) + (3 x^{2} + 5 x - 8)

11 x^{2} + 3 x - 7

Solution steps

(8 x^{2} - 2 x + 1) + (3 x^{2} + 5 x - 8)

Simplify

(8 x^{2} - 2 x + 1) + (3 x^{2} + 5 x - 8) : 8 x^{2} - 2 x + 1 + 3 x^{2} + 5 x - 8

= 8 x^{2} - 2 x + 1 + 3 x^{2} + 5 x - 8

Group like terms

= 8 x^{2} + 3 x^{2} - 2 x + 5 x + 1 - 8

Add similar elements:

8 x^{2} + 3 x^{2} = 11 x^{2}

= 11 x^{2} - 2 x + 5 x + 1 - 8

Add similar elements:

- 2 x + 5 x = 3 x

= 11 x^{2} + 3 x + 1 - 8

Subtract the numbers:

1 - 8 = - 7

= 11 x^{2} + 3 x - 7

(x - 3) (2 x^{2} - 5 x - 5)

15 \times 4

m n^{4} (m^{3} - 2 m^{2} n + 4 m n^{2} - n^{2} + 4)

x + 3 + \frac{3 x}{x + 5}

- 9 + - 28

What is (8x^2-2x+1)+(3x^2+5x-8) ?
The solution to (8x^2-2x+1)+(3x^2+5x-8) is 11x^2+3x-7