What is x/(x^2-64)-7/(4x^2+32x) ?

The solution to x/(x^2-64)-7/(4x^2+32x) is (4x^2-7x+56)/(4x(x+8)(x-8))

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simplify x/(x^2-64)-7/(4x^2+32x)

simplify

\frac{x}{x ^{2} - 64} - \frac{7}{4 x ^{2} + 32 x}

\frac{4 x ^{2} - 7 x + 56}{4 x ( x + 8 ) ( x - 8 )}

Solution steps

\frac{x}{x ^{2} - 64} - \frac{7}{4 x ^{2} + 32 x}

Least Common Multiplier of

x^{2} - 64, 4 x^{2} + 32 x : 4 x (x + 8) (x - 8)

Adjust Fractions based on the LCM

= \frac{4 x ^{2}}{4 x ( x + 8 ) ( x - 8 )} - \frac{7 ( x - 8 )}{4 x ( x + 8 ) ( x - 8 )}

Apply the fraction rule:

\frac{a}{c} - \frac{b}{c} = \frac{a - b}{c}

= \frac{4 x ^{2} - 7 ( x - 8 )}{4 x ( x + 8 ) ( x - 8 )}

Simplify

4 x^{2} - 7 (x - 8) : 4 x^{2} - 7 x + 56

= \frac{4 x ^{2} - 7 x + 56}{4 x ( x + 8 ) ( x - 8 )}

\frac{3}{3 x}

lo g_{\frac{1}{2}} (256)

\frac{512}{3}

\frac{4 x + 8}{x ^{2} - 25} \cdot \frac{x - 5}{5 x + 10}

- 8 + (- 5)

What is x/(x^2-64)-7/(4x^2+32x) ?
The solution to x/(x^2-64)-7/(4x^2+32x) is (4x^2-7x+56)/(4x(x+8)(x-8))