What are the solutions to the equation 4x^2-4x=-7 ?

The solutions to the equation 4x^2-4x=-7 are x= 1/2+isqrt(3/2),x= 1/2-isqrt(3/2)

Find the zeros of 4x^2-4x=-7

The zeros of 4x^2-4x=-7 are x= 1/2+isqrt(3/2),x= 1/2-isqrt(3/2)

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4 x^{2} - 4 x = - 7

x = \frac{1}{2} + i \frac{3}{2}, x = \frac{1}{2} - i \frac{3}{2}

Solution steps

4 x^{2} - 4 x = - 7

Move

7

to the left side

4 x^{2} - 4 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 4 \cdot 7}{2 \cdot 4}

Simplify

(- 4)^{2} - 4 \cdot 4 \cdot 7 : 46 i

x_{1, 2} = \frac{- ( - 4 ) \pm 4 6 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 4 6 i}{2 \cdot 4}, x_{2} = \frac{- ( - 4 ) - 4 6 i}{2 \cdot 4}

x = \frac{- ( - 4 ) + 4 6 i}{2 \cdot 4} : \frac{1}{2} + i \frac{3}{2}

x = \frac{- ( - 4 ) - 4 6 i}{2 \cdot 4} : \frac{1}{2} - i \frac{3}{2}

The solutions to the quadratic equation are:

x = \frac{1}{2} + i \frac{3}{2}, x = \frac{1}{2} - i \frac{3}{2}

∣ x - 4 ∣ = 0

7 (2 y - 8) = 14

2 a^{2} = - 6 + 8 a

4 m = 2 (m - 4)

3 (- 8 x - 4) + 15 \geq - 15 x + 12 or 4 x + 5 > 2 x - 11

What are the solutions to the equation 4x^2-4x=-7 ?
The solutions to the equation 4x^2-4x=-7 are x= 1/2+isqrt(3/2),x= 1/2-isqrt(3/2)
Find the zeros of 4x^2-4x=-7
The zeros of 4x^2-4x=-7 are x= 1/2+isqrt(3/2),x= 1/2-isqrt(3/2)