What is (x^2-x-6)/(x^2-9) ?

The solution to (x^2-x-6)/(x^2-9) is (x+2)/(x+3)

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simplify (x^2-x-6)/(x^2-9)

simplify

\frac{x ^{2} - x - 6}{x ^{2} - 9}

\frac{x + 2}{x + 3}

Solution steps

\frac{x ^{2} - x - 6}{x ^{2} - 9}

Factor

x^{2} - x - 6 : (x + 2) (x - 3)

= \frac{( x + 2 ) ( x - 3 )}{x ^{2} - 9}

Factor

x^{2} - 9 : (x + 3) (x - 3)

= \frac{( x + 2 ) ( x - 3 )}{( x + 3 ) ( x - 3 )}

Cancel the common factor:

x - 3

= \frac{x + 2}{x + 3}

lo g_{2} (2.5)

(4 x - 5) (2 x^{2} - 3 x - 3)

y - (- 3 y)

\frac{40}{7}

\frac{18 x ^{2} - 162 x}{9 x}