What is 2^{log_{2}(3)-log_{4}(25)} ?

The solution to 2^{log_{2}(3)-log_{4}(25)} is 3/5

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simplify 2^{log_{2}(3)-log_{4}(25)}

simplify

2^{l o g_{2} (3) - l o g_{4} (25)}

\frac{3}{5}

Solution steps

2^{l o g_{2} (3) - l o g_{4} (25)}

lo g_{2} (3) - lo g_{4} (25) = lo g_{2} (\frac{3}{5})

= 2^{l o g_{2} (\frac{3}{5})}

Apply log rule:

a^{l o g_{a} (b)} = b

2^{l o g_{2} (\frac{3}{5})} = \frac{3}{5}

= \frac{3}{5}

(3 x + 5) (2 x^{2} + x + 5)

(y + 8)^{2}

- 7 \cdot (- 7)

lo g_{3} (125)

\frac{x ^{2} + 5 x - 6}{x ^{2} - 9 x + 8} \cdot \frac{x ^{2}}{3 x + 18}

What is 2^{log_{2}(3)-log_{4}(25)} ?
The solution to 2^{log_{2}(3)-log_{4}(25)} is 3/5