What is (x^2-3x-54)/(x^2-9x)*(2x)/(x^2+8x+12) ?

The solution to (x^2-3x-54)/(x^2-9x)*(2x)/(x^2+8x+12) is 2/(x+2)

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simplify (x^2-3x-54)/(x^2-9x)*(2x)/(x^2+8x+12)

simplify

\frac{x ^{2} - 3 x - 54}{x ^{2} - 9 x} \cdot \frac{2 x}{x ^{2} + 8 x + 12}

\frac{2}{x + 2}

Solution steps

\frac{x ^{2} - 3 x - 54}{x ^{2} - 9 x} \cdot \frac{2 x}{x ^{2} + 8 x + 12}

Cancel

\frac{x ^{2} - 3 x - 54}{x ^{2} - 9 x} : \frac{x + 6}{x}

= \frac{x + 6}{x} \cdot \frac{2 x}{x ^{2} + 8 x + 12}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{( x + 6 ) \cdot 2 x}{x ( x ^{2} + 8 x + 12 )}

Cancel the common factor:

x

= \frac{( x + 6 ) \cdot 2}{x ^{2} + 8 x + 12}

Factor

x^{2} + 8 x + 12 : (x + 2) (x + 6)

= \frac{( x + 6 ) \cdot 2}{( x + 2 ) ( x + 6 )}

Cancel the common factor:

x + 6

= \frac{2}{x + 2}

\frac{4}{28}

\frac{1}{2} + \frac{1}{4} + \frac{1}{4}

- 2. 5^{2}

(- x^{2} y^{3} m)^{5}

(x - 2) (3 x^{2} + 3 x + 2)

What is (x^2-3x-54)/(x^2-9x)*(2x)/(x^2+8x+12) ?
The solution to (x^2-3x-54)/(x^2-9x)*(2x)/(x^2+8x+12) is 2/(x+2)