What is factor 256a^{12}-289b^4m^{10} ?

The solution to factor 256a^{12}-289b^4m^{10} is (16a^6+17b^2m^5)(16a^6-17b^2m^5)

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factor 256a^{12}-289b^4m^{10}

factor

256 a^{12} - 289 b^{4} m^{10}

(16 a^{6} + 17 b^{2} m^{5}) (16 a^{6} - 17 b^{2} m^{5})

Solution steps

256 a^{12} - 289 b^{4} m^{10}

256 a^{12} = (16 a^{6})^{2}

289 b^{4} m^{10} = (17 b^{2} m^{5})^{2}

= (16 a^{6})^{2} - (17 b^{2} m^{5})^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(16 a^{6})^{2} - (17 b^{2} m^{5})^{2} = (16 a^{6} + 17 b^{2} m^{5}) (16 a^{6} - 17 b^{2} m^{5})

= (16 a^{6} + 17 b^{2} m^{5}) (16 a^{6} - 17 b^{2} m^{5})

(- 2 x - 1) (2 x^{2} + 10 x + 1)

\frac{2}{3} \cdot \frac{3}{8}

(2 x - 9) (3 x + 4)

\frac{\frac{x ^{2}}{x ^{2} + 7 x + 6}}{\frac{9 x - 9}{x ^{2} - 1}}

(3 x - 1)^{4}

What is factor 256a^{12}-289b^4m^{10} ?
The solution to factor 256a^{12}-289b^4m^{10} is (16a^6+17b^2m^5)(16a^6-17b^2m^5)