What is (3x^5-2x^4-5)-(2x^4+x^2-10) ?

The solution to (3x^5-2x^4-5)-(2x^4+x^2-10) is 3x^5-4x^4-x^2+5

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simplify (3x^5-2x^4-5)-(2x^4+x^2-10)

simplify

(3 x^{5} - 2 x^{4} - 5) - (2 x^{4} + x^{2} - 10)

3 x^{5} - 4 x^{4} - x^{2} + 5

Solution steps

(3 x^{5} - 2 x^{4} - 5) - (2 x^{4} + x^{2} - 10)

Apply rule:

(a) = a

(3 x^{5} - 2 x^{4} - 5) = 3 x^{5} - 2 x^{4} - 5

= 3 x^{5} - 2 x^{4} - 5 - (2 x^{4} + x^{2} - 10)

Apply the distributive law:

- (a + b) = - a - b

- (2 x^{4} + x^{2} - 10) = - 2 x^{4} - x^{2} + 10

= 3 x^{5} - 2 x^{4} - 5 - 2 x^{4} - x^{2} + 10

Group like terms

= 3 x^{5} - 2 x^{4} - 2 x^{4} - x^{2} - 5 + 10

Add similar elements:

- 2 x^{4} - 2 x^{4} = - 4 x^{4}

= 3 x^{5} - 4 x^{4} - x^{2} - 5 + 10

Add the numbers:

- 5 + 10 = 5

= 3 x^{5} - 4 x^{4} - x^{2} + 5

\frac{81}{27}

0^{10}

(x + 6) (3 x - 8)

(\frac{x ^{3}}{4} - \frac{1}{x ^{3}})^{2}

(\frac{4 x ^{2}}{8 y ^{3}})^{2}

What is (3x^5-2x^4-5)-(2x^4+x^2-10) ?
The solution to (3x^5-2x^4-5)-(2x^4+x^2-10) is 3x^5-4x^4-x^2+5