What are the solutions to the equation 4.9x^2+8.7x-25=0 ?

The solutions to the equation 4.9x^2+8.7x-25=0 are x=(-87+sqrt(56569))/(98),x=(-87-sqrt(56569))/(98)

Find the zeros of 4.9x^2+8.7x-25=0

The zeros of 4.9x^2+8.7x-25=0 are x=(-87+sqrt(56569))/(98),x=(-87-sqrt(56569))/(98)

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4.9 x^{2} + 8.7 x - 25 = 0

x = \frac{- 87 + 56569}{98}, x = \frac{- 87 - 56569}{98}

Solution steps

4.9 x^{2} + 8.7 x - 25 = 0

Multiply both sides by

10

49 x^{2} + 87 x - 250 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 87 \pm 8 7 ^{2} - 4 \cdot 49 ( - 250 )}{2 \cdot 49}

8 7^{2} - 4 \cdot 49 (- 250) = 56569

x_{1, 2} = \frac{- 87 \pm 56569}{2 \cdot 49}

Separate the solutions

x_{1} = \frac{- 87 + 56569}{2 \cdot 49}, x_{2} = \frac{- 87 - 56569}{2 \cdot 49}

x = \frac{- 87 + 56569}{2 \cdot 49} : \frac{- 87 + 56569}{98}

x = \frac{- 87 - 56569}{2 \cdot 49} : \frac{- 87 - 56569}{98}

The solutions to the quadratic equation are:

x = \frac{- 87 + 56569}{98}, x = \frac{- 87 - 56569}{98}

x^{2} - 3 x = x - 1

1 - 0.6 L + 0.08 L^{2} = 0

40 = 4 t^{2} + 12 t

- 32 c \leq 0

6 x^{2} = 375

What are the solutions to the equation 4.9x^2+8.7x-25=0 ?
The solutions to the equation 4.9x^2+8.7x-25=0 are x=(-87+sqrt(56569))/(98),x=(-87-sqrt(56569))/(98)
Find the zeros of 4.9x^2+8.7x-25=0
The zeros of 4.9x^2+8.7x-25=0 are x=(-87+sqrt(56569))/(98),x=(-87-sqrt(56569))/(98)