What is (\frac{x-8)/(x^2-2x)}{(3x^2-24x)/(3x^2)} ?

The solution to (\frac{x-8)/(x^2-2x)}{(3x^2-24x)/(3x^2)} is 1/(x-2)

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simplify (\frac{x-8)/(x^2-2x)}{(3x^2-24x)/(3x^2)}

simplify

\frac{\frac{x - 8}{x ^{2} - 2 x}}{\frac{3 x ^{2} - 24 x}{3 x ^{2}}}

\frac{1}{x - 2}

Solution steps

\frac{\frac{x - 8}{x ^{2} - 2 x}}{\frac{3 x ^{2} - 24 x}{3 x ^{2}}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{( x - 8 ) \cdot 3 x ^{2}}{( x ^{2} - 2 x ) ( 3 x ^{2} - 24 x )}

Cancel

\frac{( x - 8 ) \cdot 3 x ^{2}}{( x ^{2} - 2 x ) ( 3 x ^{2} - 24 x )} : \frac{1}{x - 2}

= \frac{1}{x - 2}

7 x + 4^{2} - [1 0^{2} + 5 (2 x - 3) + 7 (2 x - 1)]

- 225

\frac{30}{42}

\frac{2 x + 3}{x - 8} + \frac{3 x + 7}{x - 1}

4 x + 5 x

What is (\frac{x-8)/(x^2-2x)}{(3x^2-24x)/(3x^2)} ?
The solution to (\frac{x-8)/(x^2-2x)}{(3x^2-24x)/(3x^2)} is 1/(x-2)