What is expand (x+1)(2x^2-3x-7) ?

The solution to expand (x+1)(2x^2-3x-7) is 2x^3-x^2-10x-7

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expand (x+1)(2x^2-3x-7)

expand

(x + 1) (2 x^{2} - 3 x - 7)

2 x^{3} - x^{2} - 10 x - 7

Solution steps

(x + 1) (2 x^{2} - 3 x - 7)

Distribute parentheses

= x \cdot 2 x^{2} + x (- 3 x) + x (- 7) + 1 \cdot 2 x^{2} + 1 \cdot (- 3 x) + 1 \cdot (- 7)

Simplify

x \cdot 2 x^{2} + x (- 3 x) + x (- 7) + 1 \cdot 2 x^{2} + 1 \cdot (- 3 x) + 1 \cdot (- 7) : 2 x^{3} - x^{2} - 10 x - 7

= 2 x^{3} - x^{2} - 10 x - 7

4 + 4

9 \cdot 8 \cdot 7 \cdot 6

\frac{1 + \frac{3}{5}}{2}

\frac{x ^{2} - 4 x - 5}{( x - 1 ) ^{2} - 4 ( x - 1 )}

\frac{1}{1 - sin ( θ )} + \frac{1}{1 + sin ( θ )}

What is expand (x+1)(2x^2-3x-7) ?
The solution to expand (x+1)(2x^2-3x-7) is 2x^3-x^2-10x-7