What are the solutions to the equation 3x^2=-4+8x ?

The solutions to the equation 3x^2=-4+8x are x=2,x= 2/3

Find the zeros of 3x^2=-4+8x

The zeros of 3x^2=-4+8x are x=2,x= 2/3

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3 x^{2} = - 4 + 8 x

x = 2, x = \frac{2}{3}

Decimal Notation

x = 2, x = 0.66666 \dots

Solution steps

3 x^{2} = - 4 + 8 x

Move

8 x

to the left side

3 x^{2} - 8 x = - 4

Move

4

to the left side

3 x^{2} - 8 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 3 \cdot 4}{2 \cdot 3}

(- 8)^{2} - 4 \cdot 3 \cdot 4 = 4

x_{1, 2} = \frac{- ( - 8 ) \pm 4}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 4}{2 \cdot 3}, x_{2} = \frac{- ( - 8 ) - 4}{2 \cdot 3}

x = \frac{- ( - 8 ) + 4}{2 \cdot 3} : 2

x = \frac{- ( - 8 ) - 4}{2 \cdot 3} : \frac{2}{3}

The solutions to the quadratic equation are:

x = 2, x = \frac{2}{3}

3 k^{3} + 6 k^{2}

7 x + 4 = 28

(x^{2} - 7 x) = 0

\frac{4}{5} - \frac{2}{3}

(\frac{x}{9})^{2} - \frac{2 x}{3} + 1 = 0

What are the solutions to the equation 3x^2=-4+8x ?
The solutions to the equation 3x^2=-4+8x are x=2,x= 2/3
Find the zeros of 3x^2=-4+8x
The zeros of 3x^2=-4+8x are x=2,x= 2/3