What is (x/(x^2))/(\frac{x^2+6x-27){x^2-9}} ?

The solution to (x/(x^2))/(\frac{x^2+6x-27){x^2-9}} is (x+3)/(x(x+9))

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simplify (x/(x^2))/(\frac{x^2+6x-27){x^2-9}}

simplify

\frac{\frac{x}{x ^{2}}}{\frac{x ^{2} + 6 x - 27}{x ^{2} - 9}}

\frac{x + 3}{x ( x + 9 )}

Solution steps

\frac{\frac{x}{x ^{2}}}{\frac{x ^{2} + 6 x - 27}{x ^{2} - 9}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{x ( x ^{2} - 9 )}{x ^{2} ( x ^{2} + 6 x - 27 )}

Cancel

\frac{x ( x ^{2} - 9 )}{x ^{2} ( x ^{2} + 6 x - 27 )} : \frac{x + 3}{x ( x + 9 )}

= \frac{x + 3}{x ( x + 9 )}

50 + 32

lo g_{0} (0)

\frac{x ^{2} + 2 x - 63}{x ^{2} + 6 x - 27}

- 4 q - (- 8 q) + 10

\frac{3 + 2 i}{1 - 2 i}

What is (x/(x^2))/(\frac{x^2+6x-27){x^2-9}} ?
The solution to (x/(x^2))/(\frac{x^2+6x-27){x^2-9}} is (x+3)/(x(x+9))