What are the solutions to the equation 0=x^2-7x+10 ?

The solutions to the equation 0=x^2-7x+10 are x=5,x=2

Find the zeros of 0=x^2-7x+10

The zeros of 0=x^2-7x+10 are x=5,x=2

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0 = x^{2} - 7 x + 10

x = 5, x = 2

Solution steps

0 = x^{2} - 7 x + 10

Switch sides

x^{2} - 7 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot 10 = 3

x_{1, 2} = \frac{- ( - 7 ) \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 3}{2 \cdot 1}, x_{2} = \frac{- ( - 7 ) - 3}{2 \cdot 1}

x = \frac{- ( - 7 ) + 3}{2 \cdot 1} : 5

x = \frac{- ( - 7 ) - 3}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

x = 5, x = 2

x^{2} + 3 = 4 x

(2 x + 3 i) (2 x - 3 i)

3 x^{2} - 12 x + 13 = 0

12 = 2 + 27 t - 16 t^{2}

What are the solutions to the equation 0=x^2-7x+10 ?
The solutions to the equation 0=x^2-7x+10 are x=5,x=2
Find the zeros of 0=x^2-7x+10
The zeros of 0=x^2-7x+10 are x=5,x=2