What is factor x^4y^4-8x^2y^2+12 ?

The solution to factor x^4y^4-8x^2y^2+12 is (x^2y^2-2)(x^2y^2-6)

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factor x^4y^4-8x^2y^2+12

factor

x^{4} y^{4} - 8 x^{2} y^{2} + 12

(x^{2} y^{2} - 2) (x^{2} y^{2} - 6)

Solution steps

x^{4} y^{4} - 8 x^{2} y^{2} + 12

Break the expression into groups

= (x^{4} y^{4} - 2 x^{2} y^{2}) + (- 6 x^{2} y^{2} + 12)

Factor out

x^{2} y^{2}

from

x^{4} y^{4} - 2 x^{2} y^{2} : x^{2} y^{2} (x^{2} y^{2} - 2)

Factor out

- 6

from

- 6 x^{2} y^{2} + 12 : - 6 (x^{2} y^{2} - 2)

= x^{2} y^{2} (x^{2} y^{2} - 2) - 6 (x^{2} y^{2} - 2)

Factor out common term

x^{2} y^{2} - 2

= (x^{2} y^{2} - 2) (x^{2} y^{2} - 6)

0 = x^{2} - 3 x - 28

848 + 75

x^{\frac{5}{2}} - 81 x^{\frac{1}{2}}

235 x^{2} + 0.2756 x + 0.08544 = 0

(x - 6)^{2} = 16

What is factor x^4y^4-8x^2y^2+12 ?
The solution to factor x^4y^4-8x^2y^2+12 is (x^2y^2-2)(x^2y^2-6)